What is the formula to find out the kvar required to
improve the powerfactor from .85 to .99 at 1500kw, 415v.
Answers were Sorted based on User's Feedback
The KVAR required is:
KVAR=KW(tan@1-tan@2) (where @1=cos-1(p.f1)& @2=cos-1(p.f2)
Therefore,
KVAR=KW {tan[cos-1(p.f1)]-tan[cos-1(p.f2)]}
=KW {tan[cos-1(0.85)]-tan[cos-1(0.99)]}
=KW {tan[31.79]-tan[8.11]}
=KW {0.48}
=1500 {0.48}
=720
Therefore 720 KVAR is required to improve powerfactor from
0.85 to 0.99 for 1500KW load.
NOTE:-
Excuse me if the answer is wrong.
| Is This Answer Correct ? | 14 Yes | 2 No |
Answer / alimohmad khatri
KVAR=KVA*SIN(PHI)
KW=KVA*COS(PHI)
HENCE....KVAR/KW=TAN(PHI)
KVAR=KW*TAN(PHI)
NOW, FOR P.F.(1)=COS(PHI(1))=.85 THEN TAN(PHI(1))=.6197
FOR P.F.(2)=COS(PHI(2))=.99 THEN TAN(PHI(2))=.1425
KW=1500 KW IS COMMON FOR BOTH CASE 1 & 2
REQUIRED....
KVAR=KW*[TAN{PHI(1)}-TAN{PHI(2)}]
HENCE KVAR=1500*(0.6197-0.1425)=715.8
YOU NEED TO ARRANGE CAPACITOR BANK OF 715.8 KVAR.
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / waqi
first calculate the kva at .99 and 1500kw
(cosp=kw/kva),than put the value of kva in this formula kva=
(kw)2+(kvar)2)^1/2 to caculate kvar at .99 pwr factor
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / habeebm
Dear Waqi
I am not understand your answer for the above mentioned question. Will you please solve and give us the answer for required KVAR to improve power factor from 0.85 to 0.99 for 1500KW load.
| Is This Answer Correct ? | 0 Yes | 1 No |
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