Answer Posted / habeebm

The KVAR required is:

KVAR=KW(tan@1-tan@2) (where @1=cos-1(p.f1)& @2=cos-1(p.f2)

Therefore,

KVAR=KW {tan[cos-1(p.f1)]-tan[cos-1(p.f2)]}

=KW {tan[cos-1(0.85)]-tan[cos-1(0.99)]}

=KW {tan[31.79]-tan[8.11]}

=KW {0.48}

=1500 {0.48}

=720

Therefore 720 KVAR is required to improve powerfactor from
0.85 to 0.99 for 1500KW load.

NOTE:-
Excuse me if the answer is wrong.

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