Answer / kuldeep singh sevariya

dry quantity of 1 cum wet concrete =1.54
730cft=20.67cum of wet quentity
so,dry quentity of 20.67cum=1.54*20.67=31.83cum

CEMENT=(31.83*1)/(1+1+2)=7.96cum
(Density of cement-1440kg/cum)
(7.96*1440)/50=229.176Bags

SAND=(31.83*1)/4=7.92CUM, SO, 1600*7.92=12672 KG

AGGREGATE=(31.83*2)/4=15.92 CUM
SO,1520*15.92=24198.4 KG

Answer / mohammed aijaz hussain

Volume of Wet concrete = 730 cu.ft. = 20.68 cu.m.

Volume of Dry concrete = 1.75 X 20.68 = 36.19 cu.m.

Volume of cement = 1/4 X 36.19 = 9.048 cu.m.
= 258.5 Bags

Volume of Sand = 1/4 X 36.19 = 9.048 cu.m.

Volume of Aggregate = 2/4 X 36.19 = 18.095 cu.m.

Answer / ramakrishna

cement-232 bags
sand-12.9tons
metal-570cft

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