Design an underground tank of internal dimensions 6m x 3m x
3m. The soil surrounding the tank always remains dry. The
tank shall be provided with a roof slab. The soil weighs
16000 N/m3 having an angle of repose of 30.
Answer / Kirti Agarwal
First, determine the volume (V_tank) and weight (W_tank) of the tank.n V_tank = length * width * height = 6m * 3m * 3m = 54 cubic meters.n W_tank = weight_of_concrete + weight_of_steel + weight_of_roof_slab.n Let L be the length, b be the width, and t be the thickness of the roof slab. The weight of the roof slab is: W_roof_slab = density_of_concrete * (L * b * t)n To determine the required reinforcement, let d be the depth of the steel bars, and fy_s be the yield strength of steel.n Let's assume that the weight of the concrete is evenly distributed among the walls, floor, and roof slab. Let w be the total weight of the tank, excluding the roof slab:n w = W_tank - W_roof_slabn The ultimate load that each unit area of the wall can carry is: Ultimate_Load = fy_s * d + fy_c * (b + 2 * L)n The required depth of the steel bars (d) can be determined by solving:n Ultimate_Load > (w / perimeter_of_the_tank) n Solving for d: d > ((w / perimeter_of_the_tank) - fy_c * (b + 2 * L)) / fy_s
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