Answer / dinesh

3000

Answer / venkat

let x+y=5000
(x+(10x/100))+(y+15y/100)=5600

then 110x+115y=560000
110x+115y=550000
------------------
5y=10000=========>y=2000

and at last x+y=5000=====>x+2000=5000===> x=3000
so answer is 3000(Male population)

Answer / prajit

3000

x+y=5000
1.1x+1.15y=5600

solve this equation and u will get

Answer / m.vairamanickam

3000

Answer / hashmizadeh

let x=no of men y=women
x+y=5000
1.1x+1.15y=5600 hence by solving we get x=3000&y=2000

Answer / shilpi.mangal2012

3000 males

Answer / mayank thapa

5600-5000/5000*100=12%
10. 15
12
3. 2
3/5*5000=3000

Answer / hafiz ulla

Let no. of men be x

and no. of women be 5000 - x



Population increased from 5000 to 5600

i.e. 600

men increased % = 10% of x

And women increased % = 15% of (5000 - x)



so, 10% x + 15%(5000 - x) = 600

10/100 + 15/100(5000 - x) =600

10x + 75000 - 15x = 60000

-5x = -15000

x = 3000

So, the no. of males = 3000.

Answer / pijush chakraborty

Total population 5000 now 10 & 15 % of 5000 are 500& 750. Again excess population is 5600 - 5000 i.e 600.

Now simple linkup formula ie 500 - 600 & 750 - 600 soo ratio becomes 150 : 100 i.e 3:2 i.e M = 3 & W = 2

Soo 3/5 of 5000 is 3000.

Soo total men is 3000

Answer / yogini

Total population 5000 now 10 & 15 % of 5000 are 500& 750. Again excess population is 5600 - 5000 i.e 600.

Now simple linkup formula ie 500 - 600 & 750 - 600 soo ratio becomes 150 : 100 i.e 3:2 i.e F = 3 & M = 2

Soo 2/5 of 5000 is 2000.

Soo total men is 2000

The total population of a village is 5000. The number of males and females increases by 10% and 15% respectively and consequently the population of the village becomes 5600. what was the number of males in the village

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