why the emf of a cell more than the terminal voltage when the
cell is delivering current?
Answers were Sorted based on User's Feedback
Answer / satish
The EMF is the elcromotive force independent of current
flow but when the current stats flowing in the circuit then
there i some voltage drop due to the internal
resistense.So,The net potential difference will be V=E-IR
where V is the voltage,
E is Electromotive Force,
R is internal resistance.
| Is This Answer Correct ? | 73 Yes | 16 No |
Answer / johnston
The EMF is the elcromotive force independent of current
flow but when the current stats flowing in the circuit then
there i some voltage drop due to the internal
resistense.So,The net potential difference will be V=E-IR
where V is the voltage,
E is Electromotive Force,
R is internal resistance.
| Is This Answer Correct ? | 18 Yes | 12 No |
Answer / abhishek-gaur
V=E-ir
there is som potential drop in internal resistnc of clll...
so terminal voltg is bit less
| Is This Answer Correct ? | 5 Yes | 10 No |
Answer / rakesh
it's necessary for curreny flowing in tha circuit .
beacause current flow high to low pd
, so that's required
| Is This Answer Correct ? | 8 Yes | 20 No |
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