in 3phase 50kva dg what is the full load current for single
phase laod
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Answer / vikrant
40*1000=1.732*415*I*.8
40000=575.024*I
THERE FORE I=40000/575.024=69.562314 AMPS
THEREFOR FULL LOAD AMPS OF 50KVA DG IS=69.56 AMPS
Is This Answer Correct ? | 7 Yes | 3 No |
actually i think that in 3 phase formula is p = ROOT3 VI COS$ AND in 1 phase formula will P = VI COS$
SO 40 *1000 = 220 * 0.8 ( if we consider voltage 220 volt in single phase) 40000 = 176 i
I 40000/176 = 227 AMP
40*1000 = 415*0.8 I( IF WE CONSIDER V 415 VOLT)
40000 = 332I
I= 40000/332 = 120 AMP
Is This Answer Correct ? | 0 Yes | 0 No |
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