Answer / ratnakar

as per lenz law
E1=-L1d(i)/dt
E2=-L2d(i)/dt
E1/E2=L1/L2=N1/N1=0.6/0.6=1

this question is asked in IES 2013 hope my answer is clear

Answer / achintya kumar shit

We know that, Inductance L=(N*phai)/l
So, L1/L2=N1/N2
or, 0.6/0.6=N1/N2
or, N1/N2=1

Answer / shekhar

L proportional to N^2
Since L1=L2=0.6
We can assume, N1^2=N2^2=(0.6)^2
Hence, N1/N2=1.

Answer / vinova

well frnd it cant be calculated as you can calculate mutual
inductance M = K*underoot(L1*L2)
Further M=(N1*N2)/S (s is reluctance)so the data in the
above question is insufficent to calculate N1 and N2. if it
is asssumed that both have same length l and both carry
same current and both have equal magnatic field intensity H
then it can be said that N1 and N2 are equal as H*l = N*I
here l s the length of conductor

Answer / praveen.erroju

coupling coefficient k=n2/n1
so, n2/n1 =1/k=1/0.8 = 1.25

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