9*9 1:4:8 ratio using for p cc work please tell quantity
40mm aggregate ,sand &cement
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Answer / manikandan ramia sankaran
1. 9.00m x 9.00m x .15m
= 12.15 m3
12.15/(1+4+8)[x] 1.56 = 1.458m3 of cement
sand = 4 x 1.458 = 5.832 m3 of sand
4omm agg = 8 x 1.458 = 11.664 m3
Is This Answer Correct ? | 7 Yes | 2 No |
Answer / bala
1. Consider 9.000m*9.000m*0.150m
Volume - 12.15Cu.m
* Cement - 41.31 Bags
* Sand - 6.075 Cu.m
* c.agg - 12.15 Cu.m
Is This Answer Correct ? | 4 Yes | 5 No |
9*9*0.30m(assume your units) =24.3cum
cement=84.66 say-85 bags
sand=406.87 cft say-4.06 units
coarse aggregate=800.92 say-8 units
Is This Answer Correct ? | 0 Yes | 2 No |
Answer / vikas
SUPPOSE - 9.00mtr.X 9.00mtr.X 0.20mtr. = 16.20 cum.
concrete.
Cement = 55.18 bags
fine aggregate (sand) = 7.72 cum.
coarse aggregate (metal) = 15.45 cum.
Is This Answer Correct ? | 1 Yes | 4 No |
Answer / n.lakshmanan
9*9*.100=8.1m3
cement-26.244Bags
sand-67.29cft
40mm aggregate-134.58cft
Is This Answer Correct ? | 0 Yes | 6 No |
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