IS BTech chemical distance education degree from JRN
Rajasthan vidyapeth by SSK engineering college Tamilnadu
aprooved from UGC or AICTE?
Answer / priya
Working diploma engineers are not having any option to
continue their studies...and also for chemical engineers
they don't have any other colleges other than Rajasthan
Vidyapeth University...Please do advice that if we do
B.Tech chemical engineering from this college will we get
promotion oppurtunities and do we get job in govt companies
like IOCL, HPCL??
| Is This Answer Correct ? | 11 Yes | 3 No |
how much time will take 20000 liter water to cool from 80-30 0C ? Assume all parameters constant
Define an additive?
pls send me model paper of NPCIL for executive trainee. and syllabus of executive trainee 2015.
what is extractive distillaion
PETROLEUM ENGINEERING - QUESTION 25.3 : Liquid octane has a density of 703 kilograms per cubic metre and molar mass of 114.23 grams per mole. Its specific heat capacity is 255.68 J / (mol K). (a) Find the energy in J needed to increase the temperature of 1 cubic metre of octane for 1 Kelvin. (b) At 20 degree Celsius, the solubility of liquid octane in water is 0.007 mg / L as stated in a handbook. For a mixture of 1 L of liquid octane and 1 L of water, prove by calculations that liquid octane is almost insoluble in water.
how to calculate material balnce & energy balnce
7 Answers MahaGenco, Oil India, ONGC,
What are some typical applications for glass-lined reactors?
Question 68 – Biochemical Oxygen Demand (BOD) could be calculated using the formula BOD = (DOi - DOf) (Vb / Vs) where Vb = Volume of bottle in ml, Vs = Volume of sample in ml, DOi = Initial dissolved oxygen in mg / L, DOf = Final dissolved oxygen in mg / L. (a) By using a bottle of Vb = 300 ml with sample Vs = 30 ml, find the BOD if DOi = 8.8 mg / L and DOf = 5.9 mg / L. (b) By using a bottle Vb = 600 mL with sample Vs = 100 mL, find the BOD if DOi = 8.8 mg / L and DOf = 4.2 mg / L. (c) Find the average BOD = [ Answer of (a) Answer of (b) ] / 2. (d) If the BOD-5 test for (a) - (c) is run on a secondary effluent using a nitrification inhibitor, find the nitrogenous BOD (NBOD) = TBOD - CBOD. Let TBOD = 45 mg / L and CBOD = Answer of (c).
viscosty of crude use for petroliun?
why transmission lines using 220KV.
i am going to appear vedanta written test so plz can any body suggest me for this on madhu.5393@gmail.com
What is higher heating value and lower heating value? Is it positive or negative?
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