Answer / bariumesh8

Mixture of low
relative volatility is
separated by
extractive
distilation. The 3rd
party solvent
added interact wid
all components of
mixture thus alter
relative volatility
and make
separation easier.
Solvent selection
is important.

Answer / dinesh patil

Some of the Liquid componets (suppose A & B) are difficult
to seperate under normal tempreture & pressure or due to
low boiling point difference (when the mixture is
Azotropic) So requirment of extractive distillation raise.

In extractive distillation solvent component (Suppose C)is
added in such a way that it preferably extract only one of
component among A or B and after ward distillation
operation can be done.

Answer / ravi

Extractive distillation is defined as distillation in the
presence of a miscible, high boiling, relatively
non-volatile component, the solvent, that forms no azeotrope
with the other components in the mixture.

Answer / muthukumar

when feed supplied goes to reboiler section we call it as
extractive distillation and here the third component is known
as solvent

Answer / muthukumar

Extractive distillation is one where the excess feed goes to
Re-boiler section.

Answer / rajesh kumar bhagat

In this we add a entrainer, who alter the relative volatality
of one component(minor component)of azeotropic mixture and we
distilled that component out. and major component with
entrainer will be the bottom product.

If flow rate of natural gas mixture in sweating gas unite is 460000 m3/day Can it be converted into mole/day?

1 Answers   Shell,

Question 36 - For a mixture of benzene (B), toluene (T) and xylene (X), the equation applies where x for B, T and X will sum up to 1. The equation of x for each component is x = (L / V + 1) (F) / (L / V + K). The data of F for each component are : 0.5 for B, 0.35 for T, 0.15 for X. The data of K for each component are : 1.98 for B, 0.76 for T, 0.24 for X. When x for B + x for T + x for X = 1, find the values of (a) L / V; (b) x for each component of B, T, X respectively. You may use Excel program - Data : What-If-Analysis for Goal Seek to perform the iterative calculations.

1 Answers  

What is the angle of repose and what are its applications in the chemical industry?

0 Answers  

Explain the different characteristics that can affect the flow of bulk solids and how?

0 Answers  

What is a black body?

0 Answers  

what is difference between precipitation and crystalisation

2 Answers  

Question 85 - (a) Three genes, I, J and K are available. All these genes are linked with respect to one another. If the percent recombination between I and J is 8 %, that between J and K is 10 %, and that between K and I is 18 %, what is the order of the gene? (b) Twenty six genes, a, b, c, d, e, f, ... x, y and z are available. All these genes are linked with respect to one another. If the percent recombination between a and b is 3 %, between b and c is 3 %, between c and d is 3 %, ... between w and x is 3 %, between x and y is 3 %, between y and z is 3 %, then what is the percentage recombination between b and y?

1 Answers  

why relative humidity is different in different places

3 Answers  

Explain what type of pump may be appropriate for a liquid near saturation, a low flow rate, and very limited npsha (net positive suction head available)?

0 Answers  

CHEMICAL MATERIAL BALANCE – EXAMPLE 2.2 : Three hundred gallons of a mixture containing 75.0 wt % ethanol and 25 wt % water (mixture specific gravity = 0.877) and a quantity of a 40.0 wt % ethanol - 60 wt % water mixture (specific gravity = 0.952) are blended to produce a mixture containing 60.0 wt % ethanol. The specific gravity of a substance is the ratio of density of a substance compared to the density of water. The symbol of weight percent is wt %. (a) Estimate the specific gravity of the 60 % mixture by assuming that y = mx c where y is wt % ethanol, x is mixture specific gravity. Values for m and c are constants. (b) Determine the required volume of the 40 % mixture.

1 Answers  

I want to need previous placement questions of Jindal

1 Answers   Jindal, Jindal Steel and Power,

Question 83 - The United States of America Energy Information Administration reports the following emissions in million metric tons of carbon dioxide in the world for year 2012 : Natural gas : 6799, petroleum : 11695, coal : 13787. Coal-fired electric power generation emits around 2000 pounds of carbon dioxide for every megawatt hour generated, which is almost double the carbon dioxide released by a natural gas-fired electric plant per megawatt hour generated. If 1 metric ton = 1000 kg and 1 pound = 0.4536 kg, estimate the total energy generated by natural gas in the world for year 2012, in gigawatt hour.

1 Answers