Answer / satishchemeng

By applying Law of conservation of Mass & Law of
conservation of energy to the system we can calculate
Material & Energy balance

Answer / rajesh kumar bhagat

By using conservation of mass and energy equation.

Answer / kgk kishore

Both can be calculated from the law of conservation of mass
and energy. Since Input whatever we give must come out,
above said formula can be applied in both the cases.
Input- output+ generation = Accumulation.

Answer / mahesh ritapure

by using law of mass and energy equetion

Answer / munendra

input-output+generation-consumed=accumulation

Answer / vinayak be chemical

INPUT=OUTPUT+ACCUMULATION

Answer / jyotsna s.dudhapachare

Material Balnce = Input - out put + Acumulation + Gneration

what is cv value in valves

3 Answers   IFFCO,

Question 34 – In the distillation of binary systems by Mc Cabe Thiele method, the equation for the line of top section is given by y = [ R / (R + 1) ] x + XD / (R + 1). 2 points on the line are (0.99, 0.99) and (0, 0.36). Find the reflux ratio of R and XD.

1 Answers  

What are the steps required to design a vapor-liquid separator or flash drum?

0 Answers  

QUANTUM COMPUTING - EXAMPLE 32.10 : In quantum computing, the conversion of Control Not (CNOT) gate in two input quantum bit gate could be decribed as : | 00 > --> | 00 >, | 01 > --> | 01 >, | 10 > --> | 11 >, | 11 > --> | 10 >. If | P > = 0.707 ( | 01 > - | 11 > ), find the value of CNOT | P >.

1 Answers  

What is the principles of crayogenic expansion turbin

1 Answers   Goyal Group,

when selecting psv(pressure safety valve),what are all things we have to keep it in mind?

4 Answers   Qasco,

What is the main difference between deflection and null type instruments?

1 Answers  

Water flows through a pipe with circular cross sectional area at the rate of V / t = 80 L / s where V is the volume and t is time. Let Av = 80 L / s where A is cross sectional area and v is velocity of fluid. For point 1, the radius of the pipe is 16 cm. For point 2, the radius of the pipe is 8 cm. Find (a) the velocity at point 1; (b) the velocity at point 2; (c) the pressure at point 2 by using Bernoulli’s equation where P Rgy 0.5 RV = constant. P is the pressure, R = density of fluid, V = square of fluid’s velocity, g = gravitational constant of 9.81 N / kg and y = 2 m = difference of height at 2 points. The pressure of point 1 is 180 kPa.

1 Answers  

When an expansion is joint needed on the shell side of a shell and tube heat exchanger?

0 Answers  

What type of pump may be appropriate for a liquid near saturation, a low flow rate, and very limited npsha?

0 Answers  

Explain how can I evaluate the thermal relief requirements for double block-in of 98% sulfuric acid?

0 Answers  

Question 45 - According to Raoult’s law for ideal liquid, x (PSAT) = yP where x is mole fraction of component in liquid, y is mole fraction of component in vapor, P is overall pressure and PSAT is saturation pressure. A liquid with 60 mole % component 1 and 40 mole % component 2 is flashed to 1210 kPa. The saturation pressure for component 1 is ln (PSAT) = 15 - 3010 / (T + 250) and for component 2 is ln (PSAT) = 14 - 2700 / (T + 205) where PSAT is in kPa and T is in degree Celsius. By assuming the liquid is ideal, calculate (a) the fraction of the effluent that is liquid; (b) the compositions of the liquid and vapor phases. The outlet T is 150 degree Celsius.

1 Answers