Answer / mechatronics89

let p1 = density of wood and p2 be dat of fluid.
applying force balance
p1*V*g= p2*(4/5)V*g (gravity = buoyant force)

800=.2*p2
p2=4000 kg/m^3

Answer / arul - mz

Kindly be clear in the words used in the question...

Taking the question in the following way I solve it...

The 4/5th part of volume of a piece of wood foating is sunk
in a fluid. if the relative dencity of wood is
0.8 then what will be the dencity of fluid in KG/M3.
PLEASE ANSWER WITH SOLUTION.

Assume wolume of wood = 1000 cu.m
As per the data avl...

qty immersed = 800 cu.m (4/5 th sunk)

by Archimedes principle it must have displaced 800 cu.m of
liquid.

RD=0.8 implies that
density = 800 kg/cu.m

so the mass of wood = vol of wood floating*density
= 1000*800

Den of liq. = mass of liq displaced / vol of liq
As per archimedes second law for floating bodies,
mass of liq displaced = mass of floating object

so, Den of liq = 1000*800/800=1000 kg/sq.cm

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