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single sphase energy meter measur
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Answer / rayudu rama krishna
Single phase energy meter, measures the power as per basic
formula P= Voltage X Current X power factor X hours.
The unit used is KWH. This is one unit means 1000 W power
continously supplied for one hour.
| Is This Answer Correct ? | 29 Yes | 3 No |
Answer / gurucharan singh
Single phase energy meter, measures the power as per basic
formula P= Voltage X Current X power factor X hours.
The unit used is KWHr. This is one unit means 1000 KW power
continously supplied for one hour.
| Is This Answer Correct ? | 22 Yes | 14 No |
Answer / anbuselvan
The Single Phase energy meter records the single phase power as,
P=V*I*PF*Hours.
It is also called Watt-Hour Meter.Bcaz its record the
consumption of power in terms of hourly basis.
The Speed or Torque of the Disc(In case Of Non-electronic
meter),is equal to power in watts.
Torque=Power.Torque is directly proportional to power.
| Is This Answer Correct ? | 6 Yes | 2 No |
Answer / dave.vimal
Single Phase meter is a measuring instrument which records
the energy consumed by the load in terms of 'KWH'.
The meter records the consumption based on the following
formula...
Power in KWH = Voltage x Current x Power factor x Total
number of Hours utilized
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / naresh
Single Phase meter is a measuring instrument which records
the power consumed by the load in terms of 'KWH'. The meter
records the consumption based on the following formula...
Power in KWH = Voltage x Current x Power factor x Total
number of Hours utilized.
| Is This Answer Correct ? | 4 Yes | 2 No |
The Single Phase energy meter It is also called Watt-Hour
Meter it is used for mesuring and record the
consumption of power in terms of hourly basis. an the basis
of bellow formula.
Power in KWH = Voltage x Current x Power factor xHours
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / p balaji
The energy consumed is given by
e=p*t
power(p)=v*i*powerfactor
active power=v*i*cos(phasediff)
reactive power=v*i*sin(phase diff)
Apparent power=sqrt(p square+q square)
t:time in hours
p in kilowatts
1kwh=1 unit
| Is This Answer Correct ? | 0 Yes | 5 No |
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