We have 800KW motor operating at 6600Volt,50 Hz
supply.During 1st startup it tripped on overcurrent
trip.It's FLA is 88 Amps.The K factor of Thermal overloaaad
was set on .94 initially.then we set at 0.97 and then it
started fine.i dont understand why it tripped first?What
are the protections which comes in picture during starting ?
Answers were Sorted based on User's Feedback
Answer / prabhukumar
we all know that the starting current of motor is 5 times
more than of rated current.
for the starting current also some settings will be their
in that the starting current time may be less and the
starting time the heat will be their.
You just check it out and tell me.
prabhu.jsw@gmail.com
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / ghani
It is right that starting current of this much big motor is
very high whihc varies as per data from 6 to 8 times, so if
the protection relay is of static or digital then there
must be a restraining setting for starting current with
time delay, so you can increas both values keeping the data
sheet of motor in view.
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / kiran patil
You have increased thermal overload settings to .97 I think
because of load motor gets hot early and after incresing
the themal rating it will sustain.
Is This Answer Correct ? | 5 Yes | 5 No |
Answer / a.kossay
FIRST OF ALL THIS MOTOR MUST HAVE A SOFT STARTER BECAUSE
STARTING THIS MOTOR WILL DRAW A HUGE AMOUNT OF INRUSH
CURRENT + HUGE AMOUNT OF STARTING CURRENT, SO YOU HAVE TO
USE SOFT STARTER , AND YOU HAVE TO USE SMART RELAY BECAUSE
STARTING AND INRUSH CURRENT CONATINS A HUGE AMOUNT OF
HARMONIC CONTENTS SPECIALLY THIRD HARMONIC SO THIS SMART
RELAY WILL DETECT THE VALUE OF THE THIRD HARMONIC COMPONENT
AND IF IT EXCEEDS ITS VALUE IT WILL TRIP
Is This Answer Correct ? | 2 Yes | 2 No |
Answer / karthik_elec
u did'nt mention which type of starter you used,and which type of operation no load or full load, this type large motors always used soft starter only, auto transformer will not use, any way at the time of starting auto transformer only gradually increase the applied voltage , at that time the motor will take more amps to obtain the specific torque, due to that only, after obtain normal amps it will not take 88 amps also, because this is 100% efficiency current, below that only....
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / parveen garg
I DO NOT KNOW ABOUT 6.6KV MOTORS & ALSO ABOUT K FACTOR.BUT
ACCORDING TO UR QUESTION IT LOOKS THAT MOTOR DRAW MORE
INSTANTANOUS CURRENT THAN ASSUMED BY THE CALCULATION & AT
THIS STARTING CURRENT OLR TRIPPED,WHEN U INCREASE THE
SETTING OF OLR.IT DO NOT TRIP.
FOR THE PROTECTION POINT OF VIEW ONE EXTRA CONTACTOR MAY BE
PROVIDE IN PARALLEL TO THE OPERATING CONACTOR WITH TIMER
WHICH WILL MADE OFF THE CONATCTOR(PROVIDED NEWLY)&ALSO THIS
CONTANCTOR WILL DRAW POWER FROM MAIN BUSBAR WITH EXTRA OLR .
Is This Answer Correct ? | 0 Yes | 5 No |
What is Primary and Secondary Injection Test of CT and Relay.
wich type of cable is selected for wiring of 20hp motor?
How to calculate the NGR value for a 2.7MVA Transfomer, 11KV system where the fault current has to be limited to 50A?
how to syncronize two dg sets
When calculation of fault current and fault Kva is to be done,why always we use per unit value and why we consider the base kva?
how to reduce earth to neutral voltage?
whats the formula for convert KVAR to FARADS
1000 W bulb takes 4.16 Amps at 240 volt then what will be the KWH & if i am using 1000 W bulb at 180 Volt the amps will be 5.55 then what will be KWH????????????????
For the same power rating,which motor is bigger in size,AC or DC?
which circuit takes max. load & which circuit takes min. load i.e. SERIES CIRCUIT OR PARALLEL CIRCUIT??
As per the Anchor capstan motor specification, full load current is 200A. starting current is 1750 A and acceleration time is less than 8 seconds. Please guide for selection of cable size.
What are eddy current and define rms value?