Answer / tanveer

I am Tanveer (6th sem CS) from BTLIT College. I got placed in Tech Mahindra.


TechMahindra Placement Papers | TechMahindra Interview Procedure |
TechMahindra Aptitude Questions | TechMahindra Technical Questions |
TechMahindra Interview Questions



In first round there were 525 students.
168 Students cleared aptitude.
Finally 63 students got placed.

Aptitude:-

There were 75 questionss of 5 sections. Cut off is 35. Time 60 min.


1) 10 Questions on English.

Fill in the blanks with words in correct tense.

2,3 sections also English passage reading and finding grammatical mistakes
and correcting.

4,5 sections consists of non verbal & some quantitative questions.
All are very easy to solve.


Technical round:-


They will ask about core subjects of particular branch and C, C++.

TechMahindra Placement Papers | TechMahindra Interview Procedure |
TechMahindra Aptitude Questions | TechMahindra Technical Questions |
TechMahindra Interview Questions


They asked questions from C, C++, OS, DBMS, UNIX, Microprocessor (assembly
level language), computer networks, data structure.

If u r thorough with these subjects then definitly u will clear tech
round. Be confident with all your lab programs of C, DS, ADA.


HR round:-


we were lucky that they asked only 2 general questions.

Tell about yourself ?
why did you choose this branch?

There is no elimination in hr round.

TechMahindra Placement Papers | TechMahindra Interview Procedure |
TechMahindra Aptitude Questions | TechMahindra Technical Questions |
TechMahindra Interview Questions


U can easily get through tech mahindra.

Answer / abhay verma

please describe question diploma holders interview
(computer science & engg. )

Answer / chinna

can u plz send me placement papers of tech mahindra

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SNAPDEAL QUESTIONS 1. A train is going at a speed of 60kmph towards Delhi and returned back at a speed of 30kmph. What is its average speed? ANS : (2*30*60)/(30+60) = 40kmph 2. How many different 4 letter words can be framed that have at least one vowel? ANS : 264 - 214 (total no of 4 digits words – no of words with no vowels) 3. Write an algorithm to find out a number from an array of numbers where only one number occurs once and rest all occurs twice. ANS : XOR all the numbers ,you will get the number with single occurrences . 4. Which among the following have the product of the distance between opposite sides of a regular polygon and it side equals one fourth of the area. A. hexagon B. octagon C. n=16 D. n=18 ANS : n=16.(area of regular polygon = apothem*perimeter/2 Apothem = distance between opposite sides/2 Area = (opp_side_dist * n * a )/4 Product of opp_side_dist and side of reg. polygon = opp_side_dist * a For n= 16 the ration becomes 1:4 5. Which of the following cannot be a relation between two variables? ANS = 4th diagram. 6.what will be the output of this program Void print (int n) { If (n>0) { printf(“hello”); print(n-1); } printf(“world”); } ANS : N times hello followed by N+1 times world. 7. Which among the following cannot be used for future prediction? ANS : 4th Diagram. 8. There are 25 horses. We have to find out the fastest 3 horses In one race maximum 5 horses can run. How many such races are required in minimum to get the result. ANS : 7 races (A. first run all horses = 5 races, eliminate 4th 5th of all races. B. Run horses who came 1st in those 5 races = 1 race , the horse coming first is the fastest Run horses a. 2nd and 3rd with the fastest horse (in first time race A) b. 2nd and 3rd coming horse in B. c. The horse who came 2nd with the horse(who came 2nd in race B) in race A You will have the fastest 3 horses.) 9. In a game of rolling dice you are given 2 dice and you have to roll them. Whatever is the outcome the player will win that many dollars. What should the game owner charge each player (optimum) so that he doesn’t have to bear any loss? ANS : $7 10. We have a function REV(“string”,m,n).This function is capable of reversing the caharacters in the string from mth location to nth location. e.g. REV(“abcd”,2,3)  the output will be acbd We need to swap a string from a position,e.g. SWAP(“abcdefg”,4)  output needs to be efgabcd. How can the REV function used do this. ANS : L = string length,N= position given in SWAP function. SWAP(“abcdefg”,4) = REV(REV(REV(“abcdefg”,N+1,L),1,N),1,L).

1 Answers   SnapDeal,

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2012 papers

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