Answer / kangchuentat

ACCOUNTING AND FINANCIAL ENGINEERING - ANSWER 34.12 : (i)(a) Starting cash = $60k = cost of instrument. (b) Depreciation = instrumental (cost / useful life) = $60k / 3 years = $20k / year. (c) Operating profit = revenue - labor cost - depreciation = $100k - $50k - $20k = $30k. (d) Capital expense = $60k = cost of instrument. (e) Cash from operation = operating profit + depreciation = $30k + $20k = $50k. (f) Ending cash = starting cash + cash from operation - capital expense = $60k + $50k - $60k = $50k. (ii) (a) Capital expense of year 2 = 0. (b) Starting cash of year 2 = ending cash of year 1 = $50k. (c) Depreciation value = answer in (i)(b) = $20k / year. (d) Operating profit = answer in (i)(c) = $30k. (e) Cash from operation = answer in (i)(e) = $50k. (f) Ending cash = answer in (ii)(b) + answer in (ii)(e) - answer in (ii)(a) = $50k + $50k - 0 = $100k. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

Hi, This is Naveen, plz if anybody have experience of IOCL interview, send me question.

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