QUANTUM BIOLOGY - EXAMPLE 33.2 : (a) In a biomolecule, ATP hydrolysis will produce 3 kcal / mol to 60 kcal / mol of energy, according to energy scale. Find the range of such energy generation if 2 moles of molecules involved. (b) A formula is given by ln P = ln a + b ln W where P = metabolic rate, W = body size, a = dependent of taxa, b = scaling exponent. If b is approximately 1 for plant, and b is approximately 0.75 for animal, find the relationship of P as a function of a and W in plant.
QUANTUM BIOLOGY - ANSWER 33.2 : (a) Range of energy, E = 3 kcal / mol to 60 kcal / mol. For 2 moles, multiply the range by 2 so that E = (3 x 2) to (60 x 2) kcal or E = 6 kcal to 120 kcal. (b) Let ln P = 1n a + b ln W. For plant, b = 1 approximately. Then ln P = 1n a + ln W = ln (aW), P = aW. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.
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