Answer / kangchuentat

DIFFERENTIAL EQUATIONS - ANSWER 20.2 : (a) The kinematic relationship is dx = v dt. (b) The trigonometric relationship is sin T = y / L. (c) y = -vt sin T, then dy = -v dt sin T since y / x = sin T and x = -vt for y is decreased with an increasing x. (d) dy = -v dt sin T = -v dt (y / L) = -y (v / L) dt. (e) dy / y = (-v / L) dt. Integrate both sides of equation will produce ln y = -vt / L + C, then y = exp (-vt / L + C) = (exp C) exp (-vt / L). (f) When t = 0, y = (exp C) exp (-vt / L) = (exp C) exp (0) = exp C. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

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