Answer / kang chuen tat (malaysia - pen

Answer 72 - (a) Energy gained = 150 g (77 kcal / 100 g) for potatoes + 200 g (18 kcal / 111 g) for tomatoes = 147.93 kcal. (b) 1 food Calorie = 1 Calorie = 1000 calories, then 9600 calories is 9600 calories (1 Calorie / 1000 calories) = 9.6 Calories. (c) Calories per serving size in actual experiment = 34 g (9.6 Calories / 1.75 g) = 186.51 Calories. Then difference of Calories = 210 - 186.51 = 23.49. (d) Temperature difference T in degree Celsius is same as Kelvin. Then c = 1 = 9600 calories / [ (150 g) T ] or T = 9600 / 150 = 64 degree Celsius. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

Is there any facility to complete M.TECH CHEMICal eNGINEERING IN INDIA. Any college providing the same.

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What are advantages using hollow shaft impeller?

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What is a good method of analyzing powders for composition?

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How can separation of chiral chemicals affect the chemical and/or pharmaceutical industries?

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y we do not differ b/w atomic mass and atomic wieght? from engrtauseef2008@gmail.com

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pls send me HPCL & reliance test paper for chemical engineering.....

4 Answers   BCPL, HPCL, NOCL, Reliance,

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Question 34 – In the distillation of binary systems by Mc Cabe Thiele method, the equation for the line of top section is given by y = [ R / (R + 1) ] x + XD / (R + 1). 2 points on the line are (0.99, 0.99) and (0, 0.36). Find the reflux ratio of R and XD.

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i am giving BARC Trainee exam in chemical. Can anyone tell the syllabus and question paper pattern for OCES for BARC trainee?

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Question 51 - A batch reactor is designed for the system of the irreversible, elementary liquid-phase hydration of butylene oxide that produces butylene glycol. At the reaction temperature T = 323 K, the reaction rate constant is k = 0.00083 L / (mol - min). The initial concentration of butylene oxide is 0.25 mol / L = Ca. The reaction is conducted using water as the solvent, so that water is in large excess. (a) Let the molecular weight of water is 18 g / mol and the mass of 1 kg in 1 L of water, calculate the molar density of water, Cb in the unit of mol / L. (b) Determine the final conversion, X of butylene oxide in the batch reactor after t = 45 min of reaction time. Use the formula X = 1 - 1 / exp [ kt (Cb) ] derived from material balance. (c) Find the equation of t as a function of X.

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PETROLEUM ENGINEERING - QUESTION 25.2 : (a) The American Petroleum Institute gravity, or API gravity, is a measure of how heavy or light a petroleum liquid is compared to water. Let SG = specific gravity of petroleum liquid, and V = barrels of crude oil per metric ton. Given the formula for API gravity = 141.5 / SG - 131.5 and V = (API gravity + 131.5) / (141.5 x 0.159), find the relationship of SG as a function of V. (b) An oil barrel is about 159 litres. If a cylinder with diameter d = 50 cm and height h = 50 cm is used to contain the oil, find the volume V of the cylinder in the unit of oil barrel by using the formula V = 3.142 x d x h x d / 4. (c) First reference : 1 cubic metre = 6.2898 oil barrels. Second reference : 1 cubic metre = 6.37 oil barrels. What are the 2 factors that cause the difference in such reference data?

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What do you understand by wet bulb globe temperature?

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Question 102 - (a) As an approximation, let v = Zc / 137 where v is the radial velocity for 1 s electron of an element, c is the speed of light, Z is the atomic number. For gold with Z = 79, find the radial velocity of its 1 s electron, in term of c and percentage of the speed of light. (b) As an approximation, let A x A = 1 - Z x Z / 18769 where A is the ratio of the relativistic and non-relativistic Bohr radius. Find the value of A.

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