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Question 53 - In the purchase of a machine with a period n = 8.5 years, the minimum attractive rate of return, i = 12 %, the cost P = \$55000, F = \$4000 is the salvage, annual maintenance A = \$3500. The return of the investment or equivalent uniform annual benefit is \$15000. The equivalent uniform annual cost is P (A / P, i, n) + A - F (A / F, i, n). The investment is considered acceptable only when equivalent uniform annual benefit is greater than the equivalent uniform annual cost. From the compound interest table, (A / P, i = 12 %, n = 8 years) = 0.2013, (A / P, i = 12 %, n = 9 years) = 0.1877, (A / F, i = 12 %, n = 8 years) = 0.0813, (A / F, i = 12 %, n = 9 years) = 0.0677. Prove by calculations whether the investment above is acceptable.

Question 53 - In the purchase of a machine with a period n = 8.5 years, the minimum attractive rate ..

Answer / kang chuen tat (malaysia - pen

Answer 53 - (A / P, i = 12 %, n = 8.5 years) = (0.2013 + 0.1877) / 2 = 0.1945. (A / F, i = 12 %, n = 8.5 years) = (0.0813 + 0.0677) / 2 = 0.0745. Equivalent uniform annual cost = P (A / P, i = 12 %, n = 8.5 years) + A - F (A / F, i = 12 %, n = 8.5 years) = \$55000 (0.1945) + \$3500 - \$4000 (0.0745) = \$13899.5 < \$15000 (equivalent uniform annual benefit). The investment is proven acceptable. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

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