Answer / kang chuen tat (malaysia - pen

Answer 35 : (a) 0.5 atm is 1 / 2 x 760 = 380 mm Hg. Values of k could be obtained : B : 754.12 / 380 = 1.985; T : 289.71 / 380 = 0.762; X : 91.19 / 380 = 0.240. (b) V = F / [ (L / V) + 1 ] = 100 / (0.65 + 1) = 100 / 1.65 = 60.61. L = 0.65 V = 39.39. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

Explain some of the consequences of an undersized kettle type reboiler?

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Diffrence between centrifugal & recipocating pump?

8 Answers   Essar, IOCL,

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how many TDS & TOTAL HARDNESS, PH of drinking water is recomanded for human being use.

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QUANTUM CHEMISTRY AND CHEMICAL ENGINEERING - EXAMPLE 31.2 : (a) Let | - > = 1 | x > + 0 | y >, | | > = 0 | x > + 1 | y >. Find the value of 2 | x > + 3 | y > in term of | - > and | | >. (b) Let m to be the reduced mass. Find the value of m in term of Ma and Mb where 1 / m = 1 / Ma + 1 / Mb.

1 Answers  

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MY generator water cooler inlet line height - 11 mtr inlet water line height - 7 mtr water come into the line from overhead tank, O/H tank height - 20 mtr the first tapping in the inlet line is 2" line which down to 4 mtr level plateform., second tapping in inlet water line goes to a pump 6" line installed at 4 mtr level plateform, pump capacity 200m3/hr, head- 30 mtr, hp-40. the outlet of pump of 6" water line connected to a header of 6 mtr long of 6" line, on this header the six tapping are connected, 4 nos. 3" line goes to 11 mtr height water cooler the pressure of the line is 0.15 to 0.25 kg/cm2, 2" and 4" pipe line connected to a cooler at 4 mtrlevel plateform. my question is, at 11 mtr height level the quantity of water and flow is not sufficient for my cooler, the temp. of cooler is rises much more. you are requested to suggest the modification of pipe line/ pump for take more water flow and pressure (desired pressure is 1 kg/cm2)

0 Answers   Simbhaoli Sugars,

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The power required for size reduction in crushing is???

2 Answers  

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from which book shud i will prepare for the hpcl and various company exma i m fresher and my basic is not strong could u suggest from where to start

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Explain what are some typical applications for glass-lined reactors?

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Are there any special considerations to be taken into account for combustion ammonia?

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motor vs pump

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Question 53 - In the purchase of a machine with a period n = 8.5 years, the minimum attractive rate of return, i = 12 %, the cost P = $55000, F = $4000 is the salvage, annual maintenance A = $3500. The return of the investment or equivalent uniform annual benefit is $15000. The equivalent uniform annual cost is P (A / P, i, n) + A - F (A / F, i, n). The investment is considered acceptable only when equivalent uniform annual benefit is greater than the equivalent uniform annual cost. From the compound interest table, (A / P, i = 12 %, n = 8 years) = 0.2013, (A / P, i = 12 %, n = 9 years) = 0.1877, (A / F, i = 12 %, n = 8 years) = 0.0813, (A / F, i = 12 %, n = 9 years) = 0.0677. Prove by calculations whether the investment above is acceptable.

1 Answers  

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