How to calculate stirrups cutting length in columns
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1) let cover for column be 40mm (as u have not mentioned)
formula to determine cutting length of stirrup is given below
cutting length= (2A+2B)+(24D)
A=LONGER LENGTH OF COLUMN-2XCOVER=400-40X2=320MM
B=SHORTER LENGTH OF COLUMN-2XCOVER=250-40X2=170MM
D= DIAMETER OF STIRRUP BAR IN MM
therefore
cutting length=2X320+2X170 + 24X8 =1172MM=1.172 meter
2) given cover 25mm (as u have mentioned)
formula to determine cutting length of stirrup is given below
cutting length= (2A+2B)+(24D)
A=LONGER LENGTH OF BEAM-2XCOVER=400-25X2=350MM
B=SHORTER LENGTH OF BEAM-2XCOVER=200-25X2=150MM
D= DIAMETER OF STIRRUP BAR IN MM
therefore
cutting length=2X350+2X150 + 24X8 =1192MM=1.192 meter
NOTE SLAB COVER HAS NOTHING TO DO WITH CAL.OF STIRRUPS
3) ASSUME cover 30mm (as u have NOT mentioned)
formula to determine cutting length of stirrup is given below
cutting length= (2A+2B)+(24D)
A=LONGER LENGTH OF COLUMN/2 -COVER=400/2-30=170MM
B=SHORTER LENGTH OF COLUMN-2XCOVER=250-30X2=190MM
D= DIAMETER OF STIRRUP BAR IN MM
therefore
cutting length=2X170+2X190 + 24X8 =912MM=0.912 meter EACH
Generally term stirrups are used for lateral tie for beams while term ring is used for columns.calculation of length for stirrups & ring are same. Stirrups length depend upon size of column/beam,cover,dia of stirrup's bar.Nominal cover is measured from outer face of stirrups to concrete face.Although this cover at site is measured from outer face of main bar.If cover for beam is 25 mm then, for 90 degree hook for 600x400 mm column & 10 mm dia bar as per IS Code 2502 length will be=2[(600-2x25)+(400-2x25)]+20x10mm=2000...
If there are four bar of 20mm dia on 600 mm face then for central stirrup of this side will be=[600-25-25-(20/2)-(20/2)]/3=176.66 between centre of two bars of this face,now add (20/2)+(20/2) so that outer face to outer face of 20 dia bar=196.6say 197mm. same way other side of central stirrups are calculated & then add 20 times bar dia.Add 24 xdia of bar for 135 degree hook
In IS code formula=2(A+B)+20 x bar dia. A & B are internal distance between stirrup side.
| Is This Answer Correct ? | 9 Yes | 2 No |
Answer / sfz ans
above answer plus bent deductions at every bent (IS 2502)= cutting length.
ie: for columns (2A+2B)+(24D)-(kDx4)
k= 2 upto 25mm tor steel
| Is This Answer Correct ? | 3 Yes | 2 No |
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a)If column dimensions are 250*400mm , what will be cutting length for 8mm stirrups and how to calculate it? b) If beam dimensions are 200*400mm , beam coveris 25mm , slab cover is 20mm , what will be the cutting length for stirrups? c)Column dimensions are 250*400mm , reinf. is 12nos. bar of 16mm dia , stirrups provided are two legged, what will be the length of each ring? Regards
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