Answer / mohammed abdul moid

Take footing F= 4 No's size 1.2m*1.2m. and 6No. of
16mmbars
take bottom bar 1.2m and depth 0.5m
Total length L= 1.2+0.5= 1.7mt*1000= 1700

Formula =[3.14*0.00000785*16/2*16/2*1700]*6(No of
bars)
=[3.14*0.00000785*8*8*1700]*6
=[2.6818]*6 = 16.09
=[16.09]*2(Top n Bottom bars)=32.08
=[32.08]*4(No of footings in plan)
=[128.72kgs]

Answer / mutual basha baig

Qty of steel(in kgs) =no.of bars×length of bar × unit wt of bar ×simillar objects.

@unit wt of bar =diameter of bar/162.

what are the CAD software versions you have used?

12 Answers   ERA, IES,

---

what is the praposion of M30 concrete mix.

6 Answers  

---

What are causes of cracks in outside plaster of a building and how we prevent it during constructions?

6 Answers  

---

why elongation index is not required for concreteing coarse aggregate..

2 Answers  

---

What is meant by Friction Pile?

4 Answers  

---

What is Architect-Prepared Contract?

0 Answers  

---

How many number of cement bags per running metre are required to cast pileof M-20 grade

1 Answers   Mantena,

---

How we calculate the actual diameter of the TMT Steel

8 Answers   Brigade, Kalpataru, Simplex,

---

Quality control

1 Answers   NCCL,

---

1.what is the main responsibilites of Site Engineer ? and what are main attitude ?

3 Answers   UltraTech,

---

What out turn civil works

0 Answers  

---

How to Know that veriation acceptable in CPWD Work Of 1:6 Cement Mortor Received Lab test report.

0 Answers  

---