How to calculate the quantity of cement,sand,aggregate for the area L*B*T
are 15.24 m*21.36m*0.12m in the ratio 1:2:4
can any ine explain in detail by using formulas.
Thanks in advance
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Answer / karthik rajendren
Volume of Concrete = 15.24*21.36*.12 = 39 Cum
For 1:2:4 , Req.Cement Bag = 6.46 Bag/Cum , Sand = 0.44 Cum
, Agg =0.88 Cum.
For total Requirement,Cement = 41*6.46=264.86,Sand =
.44*41=18.04Cum,Agg=.88*41=36.08 Cum
(5% wastage's for Concrete is considered)
Is This Answer Correct ? | 9 Yes | 6 No |
Answer / navjeet kumar
mixed grade 1:2:4(cement:sand:aggregate)
sum=1+2+4=7
volume of concrete=15.24*21.36*0.12=39.06cum
requirment of cement=(1/7)*39.06=5.58cum
requirment of sand=(2/7)*39.06=11.16cum
requirment of aggregate=(4/7)*39.06=22.32
you can check right or wrong by =5.58+11.16+22.32=39.06cum
so right
Is This Answer Correct ? | 1 Yes | 2 No |
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