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what is the cutting length of 90 degree bend in four corner
ring in column of 8mm dia size of column 450mmx250mm of
clear cover 20mm?
- 13 Answers
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Answer / sandeep kumar
820+220+(2*80)(i:e we take 2 hook 10d each )-5*16(i:e deduction at five corners of the ring , we take 2d each )=1320
| Is This Answer Correct ? | 19 Yes | 2 No |
Answer / devender singh
Cutting length=2*410+2*210+2*80-5*2*8=1320mm
(10d hook & deduction of 2d on each of five bends)
| Is This Answer Correct ? | 12 Yes | 1 No |
Answer / dhaval
A= 450-2*20-2*8 = 394
B= 250-2*20-2*8 = 194
length = 2*(A+B)+4*6*DIA = 2*(394+194) + 4*6*8= 1368mm
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / anurag soni
(410+410)+(210+210)+80=1320mm
1320mm cutting length of 8mm bar
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / abhi
formula 2(A+E)+24d,where A and E are inner to inner
dimension of stirrups i.e A=450-2*20-2*8=384, E=194, so
Lm= 2(384+194)+24*8= 1348mm
| Is This Answer Correct ? | 5 Yes | 5 No |
Answer / ganesan k
410*2+210*2=1240
bend 10*dia,10*8=80*4=240
cutting lenth=1480
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / rajesh singh
820+420+(2*80)(i:e we take 2 hook 10d each )-5*16(i:e
deduction at five corners of the ring , we take 2d each )=1320
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / vinay
(450+450+250+250)-8(20){dedudting covers on all 8 sides}+2*10*8{adding hook length 2*10*d}-5*2*8{deducting on all 5 sides 5*2*d}=1320mm
| Is This Answer Correct ? | 0 Yes | 0 No |
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