Answer / chinnasamy.g(mohan enterprises

cement 1m3=1440kg
1m3=35.287cft
=35.287/1440
1kg =0.024cft
=50*0.024
1bag(50kg)=1.225cft

Answer / ranjithkumar

1.25 cft

Answer / sourav sanyal

unit weight of concrete = 1440kg/cubic meter
therefore unit weight is equal to weight over volume
given the unit weight already;
1440kg/cu.m = W/V
given also the weight of cement which is 50kg
so. cross multiply and we get
v= W/unit weight = 50/1440
and the answer is = 0.0347222 cu.m.
and 1 cu.m.=35.31 c.ft.
then .0347*35.31=1.225c.ft.

Answer / thakur

1.25cft

Answer / munesh natrrajan

1.2244781 cubic ft.

Answer / m.senthilkumar

1440kg (28.80bags)=1cu.m ; 1cu.m=35.3147cu.ft

so1440kg (28.80bags)=35.3147cu.ft

50kg (1bag)=(35.3147*50)/1440

50kg (1bag)=1.2262cu.ft

Answer / gireesh puneeth

1 bag of cement 1.17cft 

Answer / anil k gadroo

1 cu m area will contain 1.2 MT of Cement (1.2 being BD)
So it means 1.2 MT of Cement =1 cum
i.e 1200 Kg of Cement = 1 cum
So 50 Kg (ie 1 bag of Cement)=(1/1200)*50=0.042cu m

Hence 1 bag= 0.042 cu m of Cement=0.137cu ft of Cement

Answer / sumonce

1 bag cement equql to 1.12 cft

Answer / sat

0.0567

01. a. Diagram of a slump cone…………… 1 b. Size of Slump Cone…………… 1 c. Volume of a slump cone by av. Dia method…………… 1 d. Volume of a slump cone by av. area method…………… 1 e. Volume of a slump cone by frustrum method …………… 1 f. Angles of slump cone …………… 1 g. Slump measured by slump cone due to…………… 1 h. Slump does not measured by cylinder / cube due to …………… 1 i) ii) i. Slump cone is to be filled in……………………..Layers.

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