ranjithkumar t


{ City } tirunelveli
< Country > india
* Profession * civil enginner
User No # 105430
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Total Answers Posted # 5

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Questions / { ranjithkumar t }
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Answers / { ranjithkumar t }

Question { L&T, 188187 }

Method of findingthe dry ingredient quantity of 1 m3
concrete.


Answer

Ref: M20=1:1.5:3
Cemet = 1/5.5*1.52*28.8= 7.95 say 8 Bags
Sand = 1.5/5.5*1.52= 0.414cum
Aggregate= 3/5.5*1.52=0.829cum

28.8 means 1 cum unit bags of concrete

Is This Answer Correct ?    0 Yes 0 No

Question { L&T, 99154 }

M20 Grade ratio?
M30 Grade ratio?
M40 Grade ratio ?


Answer

M5 - 1:5:10
M7:5 - 1:4:8
M10 - 1:3:6
M15 - 1:2:4
M20 - 1:1.5:3
M25 - 1:1:2
M30 - only design mix
M40 - only design mix

Is This Answer Correct ?    2 Yes 0 No


Question { ATS, 154711 }

how many cubic ft. for 50 kg ( 1 bag ) cement?


Answer

1.25 cft

Is This Answer Correct ?    4 Yes 0 No

Question { 86446 }

Calculate the quantity of concrete for the following.
2 Under-reamed cast in situ pile of 300 mm dia. of 10.00 m
length.


Answer

pile dia is 0.3m,
so, radious is 0.15m

quantity = 3.14*0.15*0.15*10
= 0.706
2 under reamed pile
so,
0.706*2
= 1.414 cubic meter

Is This Answer Correct ?    6 Yes 17 No

Question { Reliance, 9434 }

For 1:2:4 ratio the weight of cement is 50 kgs then how many kgs are the
weight of sand and aggregate


Answer

RATIO M15 1:2:4

CEMENT 1 Bag = 50 KG , Sand (River)=1840kg/cum,
Agg = 2850kg/cum

SAND =2/7
=0.285
=525 KG

AGG, = 4/7
=0.571
=1628kg

Is This Answer Correct ?    4 Yes 5 No