two 100W/230V bulb are connected in series. what would be
the voltage drop across 1 bulb
Answers were Sorted based on User's Feedback
Answer / sharath kumar
its the half of the voltage what we supply .. because the two bulbs have same ratings
| Is This Answer Correct ? | 12 Yes | 1 No |
Answer / vishwa theja c
(115v )half of the supply voltage across each bulb and power
consumed by each bulb will be reduced to 1/4 ae power is
proportional to square of voltage (25w).
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / dineshdamam
Applying kirchoff's voltage
law
we get the eqn
V= I*R1 + I*R2
now since both the lamps
are identical hence we get
V= 2I*R
230= 2I*R or
I*R = 115 =voltage drop
across each lamp.
| Is This Answer Correct ? | 4 Yes | 4 No |
Answer / muhammad shoaib
in series voltage drop is not same so across one bulb
voltage drop is 230v/2=150v
| Is This Answer Correct ? | 3 Yes | 3 No |
Answer / ramkrishna
p=100w
v=200
i=?
i=w/v
i=100/230=0.434
r=v/i
230/0.434=529.953917
voltage drop at 100w v=ir
v=0.434*529.953917=230v
| Is This Answer Correct ? | 8 Yes | 15 No |
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