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Suppose i have 10000 records.First time i have to load 1 to
1000 records and second run i have load 1000 to 2000
records and third load i have to load 2000 to 3000 rows .How
will achieve

Answers were Sorted based on User's Feedback



Suppose i have 10000 records.First time i have to load 1 to 1000 records and second run i have loa..

Answer / natraj

Hii Eswar can you please explain elaborately.....
thank you

Is This Answer Correct ?    1 Yes 0 No

Suppose i have 10000 records.First time i have to load 1 to 1000 records and second run i have loa..

Answer / nataraj

Hi sanajy.. thanks for ur reply... i dont want to load the
records into different files.... i need to load the same
file in different mapping runs...

Than you

Is This Answer Correct ?    0 Yes 0 No

Suppose i have 10000 records.First time i have to load 1 to 1000 records and second run i have loa..

Answer / muddam

First declare variable paramater as las_extract_date and
create port as last_updated_date and connect source.qf
transforamtion override, give as where
last_ext_dt>=last_update_date with time stamp it will work
out.

Is This Answer Correct ?    0 Yes 0 No

Suppose i have 10000 records.First time i have to load 1 to 1000 records and second run i have loa..

Answer / sujatha

Hi,
First declare mapping variable like $$rec_load in mapping tab under parameters/variables.

next in expression transformation declare one port like rec_count=setvariable($$rec_load,$$rec_load+1000)

first time $$rec_load having value zero.next time it will load 1000 records like that every run it will increment 1000 records.

Is This Answer Correct ?    1 Yes 1 No

Suppose i have 10000 records.First time i have to load 1 to 1000 records and second run i have loa..

Answer / remesh

BY USING INCREMENTAL LOADING CONCEPT

GO TO SESSION PROPERTIES--->

IN THAT U FIND OPTIONS INITIAL VALUUE AND INCREMENT VALUE
IN THAT U CAN INITIALIZE THE VALUES

Is This Answer Correct ?    0 Yes 1 No

Suppose i have 10000 records.First time i have to load 1 to 1000 records and second run i have loa..

Answer / ganesh

First declare variable parameters start value =0 and end
value=1000. Then, connect sour > seq > filter > target.
assign the seq start value = start value and end value = end
value. it will pass first 1000 records. next time increment
the variable parameter by 1000 for both start and end value.
then, it will send the next 2000 records. then, do the same
process for the remaining.

Is This Answer Correct ?    0 Yes 1 No

Suppose i have 10000 records.First time i have to load 1 to 1000 records and second run i have loa..

Answer / praveen

You can use override query in the source qualifier and set it to read rownum <= 10000. This will load the first, similar way you can do the remaining.

Is This Answer Correct ?    0 Yes 2 No

Suppose i have 10000 records.First time i have to load 1 to 1000 records and second run i have loa..

Answer / praveen hattikal

src---->sq---->exp1--->filter---->exp2---->tgt
sequence gen---^

create mapping variable $run=1000/ in exp2 $run=$run+1000

in filter sequence <$run

Is This Answer Correct ?    0 Yes 2 No

Suppose i have 10000 records.First time i have to load 1 to 1000 records and second run i have loa..

Answer / kish

Hi,

you can go for partitioning... i dont know exactly the
procedure...but this the way wat i know..... if there is any
clear explanation...it will be great...

Is This Answer Correct ?    1 Yes 4 No

Suppose i have 10000 records.First time i have to load 1 to 1000 records and second run i have loa..

Answer / eswar

it is change data capture(CDC)

Is This Answer Correct ?    0 Yes 3 No

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