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Suppose i have 10000 records.First time i have to load 1 to
1000 records and second run i have load 1000 to 2000
records and third load i have to load 2000 to 3000 rows .How
will achieve
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Answer / abhishek kumar
This qn will be solved by setcountvariable() function
variable
$$count -count .
but how.........
| Is This Answer Correct ? | 0 Yes | 3 No |
Answer / raj
BY USING INCREMENTAL LOADING CONCEPT,WE CAN LOAD THE DATA
| Is This Answer Correct ? | 0 Yes | 3 No |
Answer / natrajdreams
Hi experts please explain the following scenario.
Suppose i have 10000 records.First time i have to load 1 to
1000 records and second run i have load 1000 to 2000
records and third load i have to load 2000 to 3000 rows .How
will achieve.
thank you
| Is This Answer Correct ? | 1 Yes | 5 No |
Answer / narendar
Sir i think using Incremental Aggregation Cache
| Is This Answer Correct ? | 4 Yes | 8 No |
If you want to load these records on different files at
different time, you can use Filter transformation else u can
use Router transformation..
In Router trans create two ports and one default port.. and
write conditions according to your requirement....
| Is This Answer Correct ? | 0 Yes | 6 No |
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what is lookup ?
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Teradata 
