Interested to Buy Any Domain ? << Click Here >> for more details...
How to read multiple files at different directories using a
single Sequential File stage in DS Enterprise Edition
- 6 Answers
- 26331 Views
- TCS, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
If all files having same Metadata,
Select Read method as 'specific file(s)'
then u Can add as many files as you want to run by selecting 'file' property from the 'available properties to add'.
It locks like below:
File= /dsg/work/temp/Employee1.txt
File= /dsg/work/Employee2.txt
File= /dsg/Employee3.txt
Read Method= Specific file(s)
| Is This Answer Correct ? | 14 Yes | 0 No |
Answer / venkata ramana
To read given number of files, one can use follow below
In the sequential file stage, Use
Read Method =File Pattern
File Pattern=`ls /* | head -<Number of files to be read>`
For example, I had 5 files, with similar pattern (as
date*.txt), in working folder say "/data/working/". If we
want to read three files out of these five files, one can
use following command:
`ls /data/working/date*.txt | head -3`
Just modified Venkat's Answer based on tested job.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / satyam
sequential file stage in that option is available you can observe that, ok i will send how to process later ok
| Is This Answer Correct ? | 4 Yes | 5 No |
Answer / pooja
To read multiple files in a sequential file follow the
below process..
1. Enable "Allow Multiple Instances" in the Job Properties.
2. Add a job parameter in the sequential file stage where
the input file needs to be defined.
3. Compile and execute the job.
4. During execution, a value needs to be passed to the job
parameter..here pass the input file path placed in
different directories.
5. Execute the job for all the multiple files using the
same job by passing the input file path for each run.
6. An invocation id needs to be provided for each run. This
id indicates the no. of times the job has been executed.
Can be observed in the log.
| Is This Answer Correct ? | 5 Yes | 6 No |
Answer / venkat
To read given number of files, one can use follow below
steps:
1. In the sequential file stage, Use Read Method as
Specific File(s).
2. Now in the file text field, Put below command.
`ls /* | head -<Number of files to be read>`
This will read given number of files.
For example, I had 5 files, with similar pattern (as
date*.txt), in working folder say "/data/working/". If we
want to read three files out of these five files, one can
use following command:
`ls /data/working/date*.txt | head -3`
Hope this helps.
venkat
09940692102
| Is This Answer Correct ? | 0 Yes | 7 No |
what is flow of project?
I have 2 Files like fileA fileB Output1 Output2 Output3 1 6 1 6 11 2 7 2 7 12 3 8 3 8 13 4 9 4 9 14 5 10 5 10 15 6 11 7 12 8 13 9 14 10 15 please let know
If seg file having 10 records ex:eid 1 2 " " 10 if oracle database having 100 records ex:eid 1 2 " " 100 how to delete matched records permenently from oracle database using datastage ?
What is difference between server jobs & parallel jobs?
create a job to get the previous row salary for the current row.if there is no previous row exists for the current row,then the previous row salary should be displayed as null? empid salary previoussalary 10 1000 null 20 2000 1000 30 3000 2000 40 4000 3000
when we have to go for a sequential file stage & for a dataset in datastage?
What are routines in datastage? Enlist various types of routines.
What are the steps required to kill the job in Datastage?
Wat is isolation level and when do u use them?
How to RD using transformer?
How many types of sorting methods are available in datastage?
my source is sequencial file and my target is dataset. i am running the job in two node configuration file. my source having 10 records how the data move to target?
Teradata 
