how to find no.of records in sequntial file itself?

Question Posted / kkk

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how to find no.of records in sequntial file itself?..

Answer / varma

Option1: You can use wc –l <<filename>> | awk '{print $1}'
in “Execute command” stage to get the row count.

Option2:-Read the sequential file and after the stage
finishes successfully, you can get the link count using
DSGetLinkInfo(DSJ.ME,
DSJ.ME, “Yourlinkname”,DSJ.LINKROWCOUNT)

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how to find no.of records in sequntial file itself?..

Answer / mmmm

Hi Simha..,

If u know then only give proper ans otherwise Shutup ur
asloe.Our AllInterveiw Community give one golden award for
u.its a Simha "Gaaandu"

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14 No

how to find no.of records in sequntial file itself?..

Answer / mandru naganji

in seq file set row number column and it will generate data like 1 to n depending onm num of rows.use sort satge desc order get last record.u will get count

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how to find no.of records in sequntial file itself?..

Answer / simha

hi,

seq file --> go for options --> select row count.
then automatically updated.

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