Answer / kalyan

Dry Volume for 1 Cum Mix is 1.54 Cum.

Ratio for M25 is 1:1:2 = 1+1+2 = 4

1 Part of cement would be = 1.54/4 = 0.385 cum.

1 cum of cement = 30 bags of cement

0.385 cum of cement = 30 x 0.385 = 11.55 bags

1 bag of cement = 50 kg of cement

11.55 bags = 50 x 11.55 = 577.5 kg of cement

so the cement required is 577.5 kg for 1 cum of m25 grade.

Answer / rajkumar

25 grade mix design is 1:1:2
total = 4
cement is 1 part =1/4 = 0.25 m3 of cement
1m3 of cement =1440 kg
0.25 m3= 360 kg

Answer / pramod abhimannue

Dry Volume for 1 Cum Mix is 1.54 Cum.

Ratio for M25 is 1:1:2 = 1+1+2 = 4

1 Part of cement would be = 1.54/4 = 0.385 cum.

1 bag of cement = .035 cum

total bag of cement = 0.385/.035 = 11 bags

1 bag of cement = 50 kg of cement

11 bags = 50 x 11 = 550 kg of cement

cement required for 1 cum of m25 grade concrete is 550 kg.

Answer / ak

*M25*
Dry Volume for 1 Cum Mix is 1.54 Cum.

Ratio for M25 is 1:1:2 = 1+1+2 = 4

1 Part of cement would be = 1.54/4 = 0.385 cum.

1 bag of cement = .035 cum

total bag of cement = 0.385/.035 = 11 bags

1 bag of cement = 50 kg of cement

11 bags = 50 x 11 = 550 kg of cement

cement required for 1 cum of m25 grade concrete is 550 kg.

Answer / srinivasan.k

400kg

Answer / yedidivgp

320 kg for Reinforced Concrete
280 kg for Plain Concrete as per IS 456.

Answer / deivendran

M25 1:1:2

Cement 1/4 * 1.57 * 1440 = 565.2 kg/m^3

Sand 1/4 * 1.57 = 0.39/ CFT

20 mm metal. 2/4 * 1.57 = 0.785/ cft

Answer / sumeet vinayak

M 25 is design mix concret & raito- 1/1/2
means 1 fourth bag cement uses & normaly one fourth
means .25 m3 & 1m3 cement-1440kg & 1440 ka 1/4
1440/4 ....360kg

Answer / vidyasagar daley

from m10 to m20 are consider as nominal mix but m25 is
design mix .the ratio is also may consider as 1:1:2

calculation:

for 1cum concrete required fine,coarse aggregates are
0.46cum-fine aggregate and coarse aggregate is 0.92cum.

1(cement)/1(sand)x0.46x1440(cement
wt.kg/cum)=662kgs.or13.248bag.
(or)

25 grade mix design is 1:1:2
total = 4
cement is 1 part =1/4 = 0.25 m3 of cement
1m3 of cement =1440 kg
0.25 m3= 360 kg

Answer / amirthaganesan.m

M25 mix has a ratio of 1 cement to 1 sand and 2 stone jelly.i.e 1:1:2. This means cement volume is half of stone jelly volume.To prepare 1cu.m of concrete we need 0.0 cu.m of jelly. So we need 0.9/2= 0.45 cu.m of sand. So weight of cement required = 0.45x1440 =648 kg of cement.approximately 13 bags.

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