Answer / kalyan

Dry Volume for 1 Cum Mix is 1.54 Cum.

Ratio for M25 is 1:1:2 = 1+1+2 = 4

1 Part of cement would be = 1.54/4 = 0.385 cum.

1 cum of cement = 30 bags of cement

0.385 cum of cement = 30 x 0.385 = 11.55 bags

1 bag of cement = 50 kg of cement

11.55 bags = 50 x 11.55 = 577.5 kg of cement

so the cement required is 577.5 kg for 1 cum of m25 grade.

Answer / rajkumar

25 grade mix design is 1:1:2
total = 4
cement is 1 part =1/4 = 0.25 m3 of cement
1m3 of cement =1440 kg
0.25 m3= 360 kg

Answer / pramod abhimannue

Dry Volume for 1 Cum Mix is 1.54 Cum.

Ratio for M25 is 1:1:2 = 1+1+2 = 4

1 Part of cement would be = 1.54/4 = 0.385 cum.

1 bag of cement = .035 cum

total bag of cement = 0.385/.035 = 11 bags

1 bag of cement = 50 kg of cement

11 bags = 50 x 11 = 550 kg of cement

cement required for 1 cum of m25 grade concrete is 550 kg.

Answer / ak

*M25*
Dry Volume for 1 Cum Mix is 1.54 Cum.

Ratio for M25 is 1:1:2 = 1+1+2 = 4

1 Part of cement would be = 1.54/4 = 0.385 cum.

1 bag of cement = .035 cum

total bag of cement = 0.385/.035 = 11 bags

1 bag of cement = 50 kg of cement

11 bags = 50 x 11 = 550 kg of cement

cement required for 1 cum of m25 grade concrete is 550 kg.

Answer / srinivasan.k

400kg

Answer / yedidivgp

320 kg for Reinforced Concrete
280 kg for Plain Concrete as per IS 456.

Answer / deivendran

M25 1:1:2

Cement 1/4 * 1.57 * 1440 = 565.2 kg/m^3

Sand 1/4 * 1.57 = 0.39/ CFT

20 mm metal. 2/4 * 1.57 = 0.785/ cft

Answer / sumeet vinayak

M 25 is design mix concret & raito- 1/1/2
means 1 fourth bag cement uses & normaly one fourth
means .25 m3 & 1m3 cement-1440kg & 1440 ka 1/4
1440/4 ....360kg

Answer / vidyasagar daley

from m10 to m20 are consider as nominal mix but m25 is
design mix .the ratio is also may consider as 1:1:2

calculation:

for 1cum concrete required fine,coarse aggregates are
0.46cum-fine aggregate and coarse aggregate is 0.92cum.

1(cement)/1(sand)x0.46x1440(cement
wt.kg/cum)=662kgs.or13.248bag.
(or)

25 grade mix design is 1:1:2
total = 4
cement is 1 part =1/4 = 0.25 m3 of cement
1m3 of cement =1440 kg
0.25 m3= 360 kg

Answer / amirthaganesan.m

M25 mix has a ratio of 1 cement to 1 sand and 2 stone jelly.i.e 1:1:2. This means cement volume is half of stone jelly volume.To prepare 1cu.m of concrete we need 0.0 cu.m of jelly. So we need 0.9/2= 0.45 cu.m of sand. So weight of cement required = 0.45x1440 =648 kg of cement.approximately 13 bags.

Please let me know the simplest way of Calculating mix designs for any grade.

1 Answers   Bureau Veritas,

how i can calculate the actual nos & size of steel to make 1000sqft. x 3"thick slab

0 Answers   Alembic,

A rock anchor 3 1/2” in diameter is placed in rock. The which has an allowable shear strength of 1200 psi. Determine the required anchorage length to safely carry a 80 ton load using a 2.0:1 F.S

0 Answers   Vyom India,

How Mney Layers in 8mm plywood

3 Answers   Orbit Corporation,

How to evaluate the elastic modulus of soil from the plate load test result? for example ..one of test results are here Max. settement =4.56mm(at 900kPa) Residual settlement = 4.02mm Maximum pressure on soil 900kpa Soil bearing capacity 300kpa Plate diameter=300mm Thickness =25mm Soil description =Grey, clayey silty SAND with gravels and rock fragments

1 Answers  

how to calculate the number of bricks for 10'x10' wall?

8 Answers   STR Builders,

why the compressive strength of concrete is calculated only after 28 days.why not after 25, 26,27 days..

7 Answers  

( mean sea level )for which activity we will use this statement?

3 Answers  

among fine,coarse sand which is used for plaster, brickwork and RCC & why?

2 Answers  

What is the largest concrete dam in the world?

0 Answers  

 rcc floor to floor  4m. in column reinforcement where we provide lap in exact location.     

0 Answers   Jain Group,

what is the ration of the dummy columns which are to be dismantled in reconstruction for laying original columns

1 Answers