If a motor of 8.5 KW with same load and using in both Star
& Delta one by one,then which will take more current in
star connected or in delta connected
Answers were Sorted based on User's Feedback
Answer / subash nishad
take line voltage is VL and Zs is the impedence of
then in case of delta connection ,VP=VL
phase current I(delta)= VL/Zs
we know that in delta connection ,
Line current IL= root 3 times phase
so line current I(delta)=root3*VL/Zs
in case of star connection,Vp= VL/root3
phase current I(star)= VL/root3*Zs
weknow that in star connection,
phase current=line current
so, IL(delta)/IL(star)= root3*VL VL
---------- / ----------
= root3 *VL root3*Zs
--------- * ----------
hence, delta connection will take 3 times more current
than star connection..
|Is This Answer Correct ?||9 Yes||0 No|
IF motor is started using a delta starter then VP=VL (
Phase voltage is equall to line voltage & Load current Isc
is become root3.Isc.
Now if this motor is connected in star then then VP=VL/root3
& IP= isc /roor3
It clearly shoow that in star connection motor take 1/3
times less current then starting in Delta.
|Is This Answer Correct ?||5 Yes||2 No|
Answer / pillay
What is important is, the motor is designed to operate at
what connection and what voltage.IF it is designed for the
other connection and you powewr it the other way you will
destroy the motor winding or you wont get the intended
power out put.
power is always line voltage X LINE CURRENT x PF x root 3
for 3 phase motor, and you cannot change it.
|Is This Answer Correct ?||0 Yes||2 No|
Answer / benchalli.nagaraj
in STAR the current is more,
In star: line current = Phase current
In delta: line current =/root 3 phase current
|Is This Answer Correct ?||1 Yes||9 No|
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