Answer / sumit

Total lenth - 2*dia of bar*No.of bends

Answer / manoj

less 2*dia of bar for every bend

Answer / manish bagga

suppose size is (200*300),Cover is 25mm ,than

200-50=150
300-50=250
than, (150+250)*2+Displacement lenth(10D)
Cutting Length=880

where, dia of stirrups bar =8mm

Answer / abid khan

(L-2*cover+D-2*cover)*2+2*10d-2d*5

Answer / er shalu verma

C=((B-COVER)+(D-COVER))*2+18*d-2*d*NO OF CORNER's 90 DEGREE
BEND
WHERE,
B= BREADTH OF RECTANGULAR BEAM
D= DEPTH OF RECTANGULAR BEAM
d= DIA OF BAR

Answer / rishiv

[2(a+b)]+[2*10*d]-[2*no. of bends*d]

a=height-2*cover
b=width-2*cover
d=dia of bar

Answer / sridhar

size of Beam - covers of both side

Length of stirrup = 2*(L+B)+ (2*12dia of bar)- (3d * 5 )

Answer / raja tariq

2((L-2COVER)+(B-2COVER)) + 18D

Answer / saravanan

less the 2 cover add the 2ecery bend

Answer / ashok3388

Cutting length=total length of bar -2(number of bending * dia of bar

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