what happen when unit step signal is applied to a
integrater circuit.explain with graph
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Answer / srinivas
integrator accumulates the value
therefore the o/p will be a linear line of the form y=mx+c
where c=initial vtg on integrator
Is This Answer Correct ? | 55 Yes | 6 No |
Answer / jitendra agrawal
the transfer function of integrator is (1/s) if u integrate
this over a time period of infinity then we will get a ramp
wave whose transfer function is (1/s^2)
Is This Answer Correct ? | 32 Yes | 0 No |
Answer / sattar
the output of the integrator will be a ramp signal with
slope (-)/(+) 1/Rc ,where Rc is the time constant of the
integrator.It will continue to be in ramp nature,until it
goes to saturation stage.
| |
| | ooooooooooooooo
| (STEP I/P SIGNAL) | o
.................... | o
| | o (ramp with slope 1/rc)
| | o
|___________________ |o_______________________
Is This Answer Correct ? | 22 Yes | 3 No |
Answer / raj chakraborty
ans: ramp signal.
unit step signal is given as,
u(t)=1,for t>=0.
now integrate this function_____over 0 to t;
this will give you,
t-------as integrated value(which is ramp signal)
I think this site do not support to drew graphs
Is This Answer Correct ? | 6 Yes | 1 No |
Answer / raj chakraborty
ans: ramp signal.
unit step signal is given as,
u(t)=1,for t>=0.
now integrate this function_____over 0 to t;
this will give you,
t-------as integrated value(which is ramp signal)
I think this site do not support to drew graphs
Is This Answer Correct ? | 4 Yes | 0 No |
Answer / krishna
by considering time constant equal to 1,then apply input as
unit step signal as input.here integration of unit signal is
ramp signal.so we get output as ramp signal
Is This Answer Correct ? | 3 Yes | 0 No |
Answer / jitendra kandpal
ans is ramp fn with constant slope
integration of u(t)= 1/s*(laplace transform of u(t))
= 1/s*1/s=1/s^2
by taking inverse laplace transform i.e= r(t) (ramp function)
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / saidesh kumar
when we integrate a constant w.r.t a variable we get the
same variable as output. so unit step integration gives ramp
as the output.Integrator is simply a low pass filter.
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / greeshmaja
exponential settling to the value 1...this is the voltage
rise across the capacitor as it charges
Is This Answer Correct ? | 6 Yes | 17 No |
Answer / vivek
when unit step signal is applied to a
integrater circuit,we will gaet a triangular wave.since we
know,integration of constant becomes one degree equation.
Is This Answer Correct ? | 12 Yes | 32 No |
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