Answer / srinivas

integrator accumulates the value
therefore the o/p will be a linear line of the form y=mx+c
where c=initial vtg on integrator

Answer / jitendra agrawal

the transfer function of integrator is (1/s) if u integrate
this over a time period of infinity then we will get a ramp
wave whose transfer function is (1/s^2)

Answer / sattar

the output of the integrator will be a ramp signal with
slope (-)/(+) 1/Rc ,where Rc is the time constant of the
integrator.It will continue to be in ramp nature,until it
goes to saturation stage.
| |
| | ooooooooooooooo
| (STEP I/P SIGNAL) | o
.................... | o
| | o (ramp with slope 1/rc)
| | o
|___________________ |o_______________________

Answer / raj chakraborty

ans: ramp signal.

unit step signal is given as,
u(t)=1,for t>=0.
now integrate this function_____over 0 to t;
this will give you,
t-------as integrated value(which is ramp signal)


I think this site do not support to drew graphs

Answer / raj chakraborty

ans: ramp signal.

unit step signal is given as,
u(t)=1,for t>=0.
now integrate this function_____over 0 to t;
this will give you,
t-------as integrated value(which is ramp signal)


I think this site do not support to drew graphs

Answer / krishna

by considering time constant equal to 1,then apply input as
unit step signal as input.here integration of unit signal is
ramp signal.so we get output as ramp signal

Answer / jitendra kandpal

ans is ramp fn with constant slope
integration of u(t)= 1/s*(laplace transform of u(t))
= 1/s*1/s=1/s^2
by taking inverse laplace transform i.e= r(t) (ramp function)

Answer / saidesh kumar

when we integrate a constant w.r.t a variable we get the
same variable as output. so unit step integration gives ramp
as the output.Integrator is simply a low pass filter.

Answer / greeshmaja

exponential settling to the value 1...this is the voltage
rise across the capacitor as it charges

Answer / vivek

when unit step signal is applied to a
integrater circuit,we will gaet a triangular wave.since we
know,integration of constant becomes one degree equation.

In the OTA, the transconductance is controlled by A The ac supply voltage B A bias current C The input signal voltage D The manufacturing process

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