Answer / mechatronics89

a= 6 rad/sec^2

let Q denotes the degree ,in radians ,by which the wheel
rotates. Then we can say

Q= (1/2)*a*t^2 (since initial velocity is 0)
=.5*6*16
=48 radians..

no.of revolution = 48/2*pi = 24/pi

Answer / babytesla

Angular distance covered = 0.5((6rad/sec^2 )(1rev./2πrad)(4sec)^2) = 7.64rev

Answer / sanjay

s=u*t+(1/2)*a*t~2
s=0*4+(1/2)*6*16
s=48 Radians

One radian=180 Degree
2 radian= 360 Degree=one complete revolution

so, 24 Revolutions

Answer / xxxxxx

axial velocity=radial velocity* no. of revolution*time

acc.=axial v/t(time)

6*4=revolution n

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