Answer / md. zakir hosen

We know P=VICOSф.
Here, P=1H.P=746W,V=415v,I=1.85amp
Now putting this value on the equation simply we get the PF.
746=415*1.85*COSф
746
=>COSф=----------=0.9716 and it must be lagging.
415*1.85


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Answer / prakash veer singh

Dear Zakir husan
What is 1092 in your equation .
That we know that
p=root3 v*i*cos phi
1 h.p =746 watts = 1.732*415*1.86*cos phi
cos phi= 746/1.732*415*1.86
= 0.55 and pf leging.

Answer / aaaa

its depend on phase no of the motor.(3-phase , single phase)

Answer / vishnu

here P=1H.P=746w,
I=1.86,
V=415V

FORMULA P=1.732*V*I*COS phi
cos phi=746/1.732*415*1.86

cos phi=0.55

Answer / jagjeet

Dear Satish
The power factor dependent on the loading factor of the
induction motor , You can measure the Line current and apply
the formula suggested by Zakir or you can refer the
characteristics charts of Motor to find out the Power Factor.

Answer / shakus

@Sakthish_kumaar

Please mention whether the motor is single phase or three
phase?
apply for single phase>>

P=VIcosØ

and Apply for three phase>>

P=√3VIcosØ

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