level number 77 is used to define
a)group data
b)elementary data
c)redefine
d)none
- 8 Answers
- 9886 Views
- TCS, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / santy
level number 77 is used to define elementary data element.
| Is This Answer Correct ? | 27 Yes | 1 No |
Answer / jagannath
Both 01 and 77 level can be used to define elementary data.
| Is This Answer Correct ? | 7 Yes | 0 No |
Answer / v.s.rajashekar
LEVEL NO:77 IS USED FOR DECLARING ELEMENTRY DATA
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / siddu
level number 77 is used to define elementary data
| Is This Answer Correct ? | 1 Yes | 0 No |
1)what is use of linkage section? 2)what is difference between comp and comp-3
how many times PARA-A is performed : PERFORM PARA-A VARYING TIMES-COUNTER FROM 1 BY 1 UNTIL TIMES-COUNTER >0 PARA-A MOVE P TO Q MOVE H TO TIMES COUNTER a.10 b.1 c.11 d.0
What is a SSRANGE and NOSSRANGE?
When is a scope terminator mandatory?
How to read records in reverse order in flat file? I know we can do it by reading all records into an array.... Then read records in reverse order by using subscript or index but can any body give me the exact code.
WT R TECHNICAL MAINFRAME QUESTION ASKED IIN ANJANASOFTEARE??
I have a sequential file. How do I access a record in this sequential file randomly in my program ?
i want to learn mainframe..any websites and material to learn from basic..? my mail id : rajeswaribe2010@gmail.com
what is the difference b/w level no.01 & level no.77?
When we code these comp,comp1,comp-2,comp-3 and comp4 values. I know the differnece.I mean when we will prefer if it is new program.Explain in detail with memory examples. Thanks in advance.
.How to add one input & one Out file in existing cobol program. how approach tell me step by step.
I have a program with an Array of 5000 occurences which is being passed from 5 sub levels to the front end screen. Thess 5 programs using each 5*2 = 10 different arrays with size as 5000. This is causing the transaction to utilize more storage consupmtion. I am looking to reduce the storage consumption. As part of that initially i thought Dynamic array may solve my problem. After viewing the comments given i see its same as normal array. IS there any other way we can resolve this issue?
COBOL 
