IN TWO WATTMETER METHOD WE GOT W1,W2,WE KNOW V.HOW TO FIND Q????????????

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IN TWO WATTMETER METHOD WE GOT W1,W2,WE KNOW V.HOW TO FIND
Q????????????

Question Posted / thiru

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IN TWO WATTMETER METHOD WE GOT W1,W2,WE KNOW V.HOW TO FIND Q????????????..

Answer / kiran

active power P = W1+W2

reactive power Q = 1.732(W1-W2)

so power factor cos theta = Tan-1((1.732(W1-W2)/(w1+w2))

i.e. cos theta = tan-1(reactive power/active power)

Is This Answer Correct ?

7 Yes

0 No

IN TWO WATTMETER METHOD WE GOT W1,W2,WE KNOW V.HOW TO FIND Q????????????..

Answer / raju

1.732(w1-w2)

Is This Answer Correct ?

13 Yes

7 No

IN TWO WATTMETER METHOD WE GOT W1,W2,WE KNOW V.HOW TO FIND Q????????????..

Answer / mona

reactive power=sqrt(3)(w1-w2)

Is This Answer Correct ?

6 Yes

1 No

IN TWO WATTMETER METHOD WE GOT W1,W2,WE KNOW V.HOW TO FIND Q????????????..

Answer / ravi gurubelli

we know W1 and W2

so real power P = W1+W2

Reactive power Q= sqrt3 (W1-W1)

Is This Answer Correct ?

7 Yes

3 No

IN TWO WATTMETER METHOD WE GOT W1,W2,WE KNOW V.HOW TO FIND Q????????????..

Answer / rajeshwar rao

1.732(w1-w2)=Q and P=w1+w2
tan∅= (√3(W1-W2)/((W1+W2))

Is This Answer Correct ?

3 Yes

0 No

IN TWO WATTMETER METHOD WE GOT W1,W2,WE KNOW V.HOW TO FIND Q????????????..

Answer / gopi

reactive power Q= sqrt3 (W1-W1)

Is This Answer Correct ?

3 Yes

3 No

IN TWO WATTMETER METHOD WE GOT W1,W2,WE KNOW V.HOW TO FIND Q????????????..

Answer / viswanadh.m

w1+w2/2

Is This Answer Correct ?

3 Yes

4 No

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