ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.36 : Du Pont analysis is used to perform calculation on Return On Equity (ROE) for an engineering organization. Let Net Income = A; Earning Before Tax (EBT) = B; Earning Before Interest, Tax (EBIT) = C; Sales = D; Assets = E; Equity = F. In 5-step Du Pont formula, let Tax Burden = G = A / B; Interest Burden = H = B / C = 1.04; EBIT % = I = C / D = 0.27; Asset Turnover = J = D / E = 0.66; Leverage = K = E / F = 2.66; ROE = L = A / F. If (1 / G) = (4 / 3) : (a) find the value of L; (b) calculate the values of A, B, C, E and F when D = $1500; (c) verify the answer (b) is correct by using the answer (a).
ACCOUNTING AND FINANCIAL ENGINEERING - ANSWER 34.36 : (a) (L = A / F) = (G = A / B) (H = B / C) (I = C / D) (J = D / E) (K = E / F) = (3 / 4) (1.04) (0.27) (0.66) (2.66) = 0.37. (b) When D = $1500 : C / D = 0.27, C = 0.27 D = 0.27 ($1500) = $405. B / C = 1.04, B = 1.04 C = 1.04 ($405) = $421.20. A / B = 3 / 4, A = 3 B / 4 = 3 ($421.20) / 4 = $315.90. D / E = 0.66, E = D / 0.66 = ($1500) / 0.66 = $2272.73. E / F = 2.66, F = E / 2.66 = ($2272.73) / 2.66 = $854.41. Finally : A = $315.90, B = $421.20, C = $405, E = $2272.73, F = $854.41. (c) From answer (a), L = 0.37. From answer (b), A = $315.90, F = $854.41. Verification : L = A / F = ($315.90 / $854.41) = 0.37. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; firstname.lastname@example.org; http://kangchuentat.wordpress.com.
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A concentric, counter-current heat exchanger is used to cool lubricating oil. Water is used as the coolant. The mass flow rate of oil into the heat exchanger is 0.1 kg / s = FO. For oil, the inlet temperature TIO = 100 degree Celsius and the outlet temperature TOO = 55 degree Celsius. For water, the inlet temperature TIW = 35 degree Celsius and the outlet temperature TOW = 42 degree Celsius. What is the mass flow rate of water in kg / s, FW needed to maintain these operating conditions? Constant for heat capacity of oil is CO = 2131 J /(kg K) and for water is CW = 4178 J /(kg K). Use the equation (FO)(CO)(TIO – TOO) = (FW)(CW)(TOW – TIW).
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