Answer / kangchuentat

QUANTUM COMPUTING - ANSWER 32.7 : | + > = 0.707 ( | 0 > + | 1 > ), | - > = 0.707 ( | 0 > - | 1 > ), | + > + | - > = 0.707 ( | 0 > + | 1 > ) + 0.707 ( | 0 > - | 1 > ) = 0.707 ( | 0 > + | 1 > + | 0 > - | 1 > ) = 0.707 ( 2 | 0 > ). | Ψ (t = 0) > = | 0 > = [ 1 / (0.707 x 2) ] ( | + > + | - > ) = 0.707 ( | + > + | - > ) (Proven). The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

How can separation of chiral chemicals affect the chemical and/or pharmaceutical industries?

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i have done B.TECH in che.tech.and doing MBA . why you doing mba why u have not join any job.

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i m a frsh chemical engineer now i m confuse to attend the interview so anybody pls send model question papers to this christ_vivek33@yahoo.com

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In a crusher where is the energy provided to it is used up for?

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QUANTUM COMPUTING - EXAMPLE 32.6 : (a) Let H | 0 > = 0.707 ( | 0 > + | 1 > ), H | 1 > = 0.707 ( | 0 > - | 1 > ). Find the values for H | 0 > + H | 1 > and H | 0 > - H | 1 >. (b) In quantum computing, a qubyte is a quantum byte, or 8 quantum bits, a sequence processed as a unit. A qubit is a quantum bit. According to Alexander Holevo in his theorem, n qubits cannot carry more than n classical bits of information. What is the maximum amount of classical bits of information that can be carried by 1 qubyte.

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QUANTUM CHEMISTRY AND CHEMICAL ENGINEERING - EXAMPLE 31.5 : In a wavefunction, let P(x) = A cos kx + B sin kx. By using the boundary conditions of x = 0 and x = l, where P(0) = P(l) = 0, prove by mathematical calculation that P(x) = B sin (npx / l) where p = 22 / 7 approximately, n is a rounded number. A, B and k are constants.

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