Answer / kangchuentat

PROCESS DESIGN - ANSWER 21.3 : (a) dP = (4 psi / 10 ft) x 60 ft = 24 psi. (b) dP = 9 + 10 = 19 psi minimum. (c) P of pump = 8 + 50 = 58 psi. (d) dP for pipe = Answer of (c) - Answer of (a) - Answer of (b) = 58 - 24 - 19 = 15 psi. Maximum length of pipe = (100 ft / 2 psi) x 15 psi = 750 feet. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

What is condensate lift?

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what is meant by runaway temperature in a reactor?

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Heat transfer: In a triple effect evaporator, the heat transfer for an evaporator is calculated as q = UA (TI - TF) where TI is the initial temperature, TF is the final temperature; U and A are constants. Given that heat transfer for the first evaporator : q(1) = UA (TI - TB); second evaporator : q(2) = UA (TB - TC); third evaporator : q(3) = UA (TC - TF) where q(x) is the heat transfer function, TB is the temperature of second inlet and TC is the temperature of third inlet, prove that the overall heat transfer Q = q(1) q(2) q(3) = UA (TI - TF).

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