As we know multiplicity factor derivation equation is as below MF = main c t ra

As we know multiplicity factor derivation equation is as below
MF = main c t ratio / main p t ratio * meter c t ratio / meter p t ratio * meter dial constant
Where in digital meters for HT kwh import export now a days meter constant are calibrated already which is 1
So my question is For HT 11kv 110 v line values are as below
Main c t and p t ratio are 11000 v and 110 v and 20/5 means 20 amp and 5 amp
Now meter values are 11000/√3/110√3 and primary and secondary amp are displayed as -/5 amp on kwh meter so what will be the MF for this meter ?

Question Posted / sameer

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As we know multiplicity factor derivation equation is as below MF = main c t ratio / main p t ratio..

Answer / sameer

As i know it will be as below if wrong kindly solve it
MF=
11000/100*20/5/11000/110*5/5=4
Where meter ratings are -/5amp so i have taken primary and secondary both current 5 amp m i right ???????

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