Answer / Vipin Sonkar

When a phase is shorted to ground on the star-connected side, an unbalanced three-phase system results. The neutral point in the star connection becomes grounded, and the delta-connected primary side appears as a single-phase load. The current flows through two phases in the delta connected side, whereas the faulty phase (shorted to ground) does not contribute current to the delta side. This is due to Kirchhoff's Current Law, which states that the sum of currents entering and leaving each node in a circuit must be zero. Since the faulty phase has no connection with the neutral point in the delta configuration, it does not affect the current flow in the other two phases.

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