Answer / chaudhary_1989

data task;
input id date date9. visit ;
cards;
101 01jan2015 1
101 02jan2015 2
101 06jan2015 3
102 04jan2015 1
102 07jan2015 2
102 12jan2015 3
103 06jan2015 1
103 13jan2015 2
;
run;

Answer

data task1;
set task;
by id;
date1=lag(date);
if first.id ne 1 then x=date-date1;
run;

proc print; run;

proc transpose data = task out = b;
var date;
by id;
run;

data new;
set b;
x=col2-col1;
y=col3-col2;
run;

proc print; run;

Below is the table. Required to be output should be the highest number of each student_id. Example. Student_id Subject Marks 1 Hindi 86 2 Hindi 70 3 English 80 . Calculate sum and average marks for each group of student_id Example. Student_id Subject Marks Total Marks Average 1 English 40 181 60.33333 2 English 67 196 65.33333 3 English 80 160 53.33333 PLEASE PROVIDE THE CODE OF ABOVE PROBLEMS

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