Answer / manu varghese

M20 RATIO=1:1.5:3 TOATAL=5.5
1/5.5*50=9.091CUM
9.091*1440=13090.908KG
13090.908/50=261.8=262BAG

Answer / krishanu

I think 50m3 concrete volume is the dry volume of concrete. So wet volume of the concrete is 1.54x50=77m3
for M20 concrete the aggregate ratio is 1:1.5:3
1. So, cement required= (1x77/5.5)=14m3=14x1440=20160kg=403.2 approx 404 bags
2. sand required = (1.5x77/5.5)= 21 m3
3. stone chips required = (3x77/5.5)= 42 m3

Answer / 7418640460

For M20, Ratio 1:1.5:3
So , 1440/3 =480[cement bag 1 nos =50kg], 480/50=9.6
9.6*1.25 [1.25=1 cft]
cement = 12cft per m^3
sand = 9.6*1.5 [1.5=ratio] =14.4cft
aggregate= 9.6*3 [3= ratio] =28.8cft

Answer / puneet agnihotri

for M20,ratio is 1:1.5:3
so,x+1.5x+3x=50
5.5x=50
x=9.09
cement:9.09m^3
sand:13.635 m^3
aggregate:27.27 m^3

Answer / falji chaudhary

for m20 ratio 1:1.5:3 use by 50 cum
Cement 320 bag
Sand:39 tone
aggregte 56 tone
Water 9000 liter

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