Answer / sudesh

according to IEE regulations recommended voltage drop is 3%.
voltage drop=(400x3)/100
=12V
if we select 35sqmm pvc/xlpe/cu cable, it can carry 158A max.current.
so now we should consider about voltage drop of cable.
true voltage drop=volt.drop for cable*Current*Distance
=1.15mV/A/m * 125A * 50m
=7.18V
7.18 < 12
so 35sqmm cable would be best to carry 125A current.

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