A wattmeter is marked 15 A/30A, 300V/600V and its scale is marked up to 4500 watt. When the meter is connected for 30A, 1600V, the pointer indicates 2000 watts. The actual power in the circuit in
Answer / sudip saren
Power consumed(wattmeter)=ct ratio*pt ratio*vi*cos$
2000=(15/30)*(300/600)*600*30*cos$
or, cos$=0.44
P actual=VIcos$=600*30*0.44=8000w
Is This Answer Correct ? | 44 Yes | 8 No |
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